C++ Program to check whether a number is Armstrong or not?

What is an Armstrong number?

A three digit number is an Armstrong number if sum of cube of its digits is equal to itself.

Program:

#include<iostream>

using namespace std;

int armstrong(int x);

int cube(int c);

int main()

{

int num;

cout<<"Enter a three digit Number="<<endl;

cin>>num;

    if(armstrong(num)==num)

    {

    cout<<"Number is Armstrong";

    }

    else

    {

    cout<<"Number is not Armstrong";

    }

return 0;

}

//Armstrong Function

int armstrong(int x)

{

int a,sum=0,result;

/* a=x%10;

b=x/10;

c=b%10;

d=b/10;

int result;

result=cube(a)+cube(c)+cube(d);

return result;*/

do

{

a=x%10;

sum=sum+cube(a);

x=x/10;

}while(x!=0);

result=sum;

return result;

}

//Cube Function

int cube(int c)

{

int r;

r=c*c*c;

return r;

}

Output: